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# Ferric Oxide Crystallises in a Hexagonal Close-packed Array of Oxide Ions with Two Out of Every Three Octahedral Holes Occupied by Ferric Ions. Derive the Formula of the Ferric Oxide. - CBSE (Science) Class 12 - Chemistry

ConceptConcept of Close Packed Structures

#### Question

Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

#### Solution

Let the number of oxide (O2−) ions be x.

So, number of octahedral voids = x

It is given that two out of every three octahedral holes are occupied by ferric ions.

So, number of ferric (Fe3+) ions=2/3x

Therefore, ratio of the number of Fe3+ ions to the number of O2− ions,

Fe3+ : = O^(2-)  = 2/3x:x

= 2/3 :1

= 2 : 3

Hence, the formula of the ferric oxide is Fe2O3.

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Solution Ferric Oxide Crystallises in a Hexagonal Close-packed Array of Oxide Ions with Two Out of Every Three Octahedral Holes Occupied by Ferric Ions. Derive the Formula of the Ferric Oxide. Concept: Concept of Close Packed Structures.
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