#### Question

Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find

1)the area covered by the roads.

2) the cost of constructing the roads at the rate of Rs 110 per m^{2}.

#### Solution

Length (l) of field = 90 m

Breadth (b) of field = 60 m

Area of field = 90 × 60 = 5400 m^{2}

Length of road PQRS = 90 m

Length of road ABCD = 60 m

Width of each road = 3 m

Area of the roads = ar (PQRS) + ar (ABCD) − ar (KLMN)

= (90 × 3) + (60 × 3) − (3 × 3)

= 270 + 180 − 9 = 441 m^{2}

Cost for constructing 1 m^{2} road = Rs 110

Cost for constructing 441 m^{2} road = 110 × 441 = Rs 48510

Is there an error in this question or solution?

Solution Through a Rectangular Field of Length 90 M and Breadth 60 M, Two Roads Are Constructed Which Are Parallel to the Sides and Cut Each Other at Right Angles Through the Centre of the Fields. If the Width of Each Road is 3 M, Find Concept: Concept of Application of Conversion.