#### Question

A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:

1) the area of the verandah

2) the cost of cementing the floor of the verandah at the rate of Rs 200 per m^{2}.

#### Solution

1)

Length (l) of room = 5.5 m

Breadth (b) of room = 4 m

Area of room = l × b = 5.5 × 4 = 22 m^{2}

From the figure, it can be observed that the new length and breadth of the room, when verandah is also included, are 10 m and 8.5 m respectively.

Area of the room including the verandah = 10 × 8.5 = 85 m^{2}

Area of verandah = Area of the room including the verandah − Area of room

= 85 − 22 = 63 m^{2}

2)

Cost of cementing 1 m^{2} area of the floor of the verandah = Rs 200

Cost of cementing 63 m^{2} area of the floor of the verandah = 200 × 63

= Rs 12600