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If (X^2 + Y^2)/(X^2 - Y^2) = 2 1/8` Find X/Y - Mathematics

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Question

If `(x^2 + y^2)/(x^2 - y^2) = 2 1/8` find `x/y`

Solution

Given (x^2 + y^2)/(x^2 - y^2) = `2 1/8` find `x/y`

`(x^2 + y^2)/(x^2 - y^2) = 17/8`

Applying componendo and dividendo

`(x^2 + y^2 + x^2 - y^2)/(x^2 + y^2 - x^2 + y^2) = (17 + 8)/(17 - 8)`

`(2x^2)/(2y^3) = 25/9`

`x/y = 5/3 = 1 2/3`

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APPEARS IN

 Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 7: Ratio and Proportion (Including Properties and Uses)
Exercise 7(D) | Q: 20.1 | Page no. 102

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Solution If (X^2 + Y^2)/(X^2 - Y^2) = 2 1/8` Find X/Y Concept: Componendo and Dividendo Properties.
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