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If (X^2 + Y^2)/(X^2 - Y^2) = 2 1/8 Find `(X^3 + Y^3)/(X^3 - Y^3) - ICSE Class 10 - Mathematics

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Question

if `(x^2 + y^2)/(x^2 - y^2) = 2 1/8` find `(x^3 + y^3)/(x^3 - y^3)`

Solution

`(x^3 + y^3)/(x^3 - y^3)`

`= ((x/y)^3  + 1)/((x/y)^3 - 1)`

`= ((5/3)^2 + 1)/((5/3)^3 - 1 )`

`= (125/27 + 1)/(125/27 - 1)`

`= ((125 + 27)/27)/((125 - 27)/27)`

`= (125 + 27)/(125 - 27)`

`= 76/49 = 1  27/49`

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APPEARS IN

 Selina Solution for Selina ICSE Concise Mathematics for Class 10 (2018-2019) (2017 to Current)
Chapter 7: Ratio and Proportion (Including Properties and Uses)
Ex.7D | Q: 24.2

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Solution If (X^2 + Y^2)/(X^2 - Y^2) = 2 1/8 Find `(X^3 + Y^3)/(X^3 - Y^3) Concept: Componendo and Dividendo Properties.
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