Maharashtra State BoardSSC (English Medium) 9th Standard
Advertisement Remove all ads

Compare the Following Pairs of Ratios. - Algebra

Sum

Compare the following pair of ratios.
`sqrt80/sqrt48 , sqrt45/sqrt27`

Advertisement Remove all ads

Solution

`sqrt80 xx sqrt27 = sqrt (16 xx 5) xx sqrt ( 9 xx 3) = 4sqrt5 xx 3sqrt3 = 12sqrt15`
`sqrt45 xx sqrt48 = sqrt( 9 xx 5) xx sqrt( 16 xx 3) = 3sqrt5 xx 4sqrt3 = 12sqrt15`
Now, `12sqrt15 = 12sqrt15`
`therefore sqrt80/sqrt 48 = sqrt45/sqrt27` 

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Balbharati Mathematics 1 Algebra 9th Standard Maharashtra State Board
Chapter 4 Ratio and Proportion
Practice Set 4.2 | Q 3.4 | Page 63
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×