Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.
(R = 0.0821 L atm K−1 mol−1, Molar mass of K2SO4 = 174 g mol−1)
w2 = 2.5 × 10−2 g (Mass of K2SO4) and M2 = 174 g mol−1 (Molar mass of K2SO4)
V = 2L, R = 0.0821 L atm K−1 mol−1 and T = 25°C = 298 K
Osmotic pressure, ` pi=(w_2RT)/(M_2V)`
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