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Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated. - CBSE (Science) Class 12 - Chemistry

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Question

Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.

(R = 0.0821 L atm K−1 mol−1, Molar mass of K2SO4 = 174 g mol−1)

Solution

w2 = 2.5 × 10−2 g (Mass of K2SO4) and M2 = 174 g mol−1 (Molar mass of K2SO4)

V = 2L, R = 0.0821 L atm K−1 mol−1 and T = 25°C = 298 K

Osmotic pressure, ` pi=(w_2RT)/(M_2V)`

`pi=(2.5xx10^(-2)xx0.0821xx298)/(174xx2)=(61.1645xx10^(-2))/348=1.76xx10^(-3)atm`

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Solution Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated. Concept: Colligative Properties and Determination of Molar Mass - Osmosis and Osmotic Pressure.
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