Share

# Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated. - CBSE (Science) Class 12 - Chemistry

ConceptColligative Properties and Determination of Molar Mass Osmosis and Osmotic Pressure

#### Question

Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.

(R = 0.0821 L atm K−1 mol−1, Molar mass of K2SO4 = 174 g mol−1)

#### Solution

w2 = 2.5 × 10−2 g (Mass of K2SO4) and M2 = 174 g mol−1 (Molar mass of K2SO4)

V = 2L, R = 0.0821 L atm K−1 mol−1 and T = 25°C = 298 K

Osmotic pressure,  pi=(w_2RT)/(M_2V)

pi=(2.5xx10^(-2)xx0.0821xx298)/(174xx2)=(61.1645xx10^(-2))/348=1.76xx10^(-3)atm

Is there an error in this question or solution?

#### Video TutorialsVIEW ALL [1]

Solution Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated. Concept: Colligative Properties and Determination of Molar Mass - Osmosis and Osmotic Pressure.
S