HSC Science (Computer Science) 12th Board ExamMaharashtra State Board
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# Calculate the mole fraction and molality of HNO3 in solution contaning 12.2%HNO3 (Given atomic mases:H=1, N=13,O=16) - HSC Science (Computer Science) 12th Board Exam - Chemistry

ConceptColligative Properties and Determination of Molar Mass - Introduction

#### Question

Calculate the mole fraction and molality of HNO3 in solution contaning 12.2%HNO3 (Given atomic mases:H=1, N=13,O=16)

#### Solution

%purity = 12.2 %

∴mass of solute = 12.2 g.

mass of solvent = 100 – 12.2

= 87.8 g

:."Mole of solute"=12.2/63=0.193

:."Mole of solvent"=87.7/18=4.877

:."mole fraction of solute"=0.193/(0.193+4.877)

=0.193/5.07

= 0.038

Mole fraction of HNO3 = 0.038

"Molality of HNO"_3 = "Mass of HNO"_3/("Molar mass of HNO"_3 xx "mass of solvent")

"molality"=W_2/M_2.(1000)/W_1

=12.2/63xx1000/87.8

=12200/5531.4

= 2.2056

∴ Molality = 2.2056 mol/kg

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#### APPEARS IN

2012-2013 (March) (with solutions)
Question 3.1 | 3.00 marks

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Solution Calculate the mole fraction and molality of HNO3 in solution contaning 12.2%HNO3 (Given atomic mases:H=1, N=13,O=16) Concept: Colligative Properties and Determination of Molar Mass - Introduction.
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