#### Question

The water bills (in rupees) of 32 houses in a certain street for the period 1.1.98 to. 31.3.98 are given below:

56, 43, 32, 38, 56, 24, 68, 85, 52, 47, 35, 58, 63, 74, 27, 84, 69, 35, 44, 75, 55, 30, 54, 65, 45, 67, 95, 72, 43, 65, 35, 59.

Tabulate the data and resent the data as a cumulative frequency table using 70-79 as one of the class intervals.

#### Solution

The minimum bill is 24. Rs

Maximum bill is Rs 95.

Range = maximum bill – minimum bill

= 95-24

=71

Given class in terval is 70-79, So class size

= 79-70 = 9

∴ Number of classes =`"Range"/"Class size"=71/9`

=7.88

∴ Number of classes = 8

The cumulative frequency distribution table is as

Bills | No. of houses (Frequency) | Cumulative frequency |

16-25 | 1 | 1 |

25-34 | 3 | 4 |

34-43 | 5 | 9 |

43-52 | 4 | 13 |

52-61 | 7 | 20 |

61-70 | 6 | 26 |

70-79 | 3 | 29 |

79-88 | 2 | 31 |

88-97 | 1 | 32 |

Is there an error in this question or solution?

Solution The Water Bills (In Rupees) of 32 Houses in a Certain Street for the Period 1.1.98 To. 31.3.98 Are Given Below: 56, 43, 32, 38, 56, 24, 68, 85, 52, 47, 35, 58, 63, 74, 27, 84, 69, 35, 44, 75, 55, Concept: Collection of Data.