HSC Science (General) 12th Board ExamMaharashtra State Board
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A Coil of 100 Turns, Each of Area 0.02m^2 is Kept in a Uniform Field of Induction 3.5 X10^-5 T. - HSC Science (General) 12th Board Exam - Physics

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Question

A coil of 100 turns, each of area 0.02m2 is kept in a uniform field of induction 3.5 x10-5 T. If the coil rotates with a speed of 6000 r.p.m. about an axis in the plane of the coil and perpendicular to the magnetic induction, calculate peak value of e.m.f. induced in the coil.

Solution

Given: f = 6000 r.p.m = 100 Hz, N = 100, A = 0.02 m2, B = 3.5  10-5 T

To find: peak e.m.f (e0)

Formula: e0 = 2πfBNA

Calculation: From formula,

e0 = 2 x 3.14 x 100 x 100 x 0.02 x 3.5 x 10-5

∴ e0 = 43.99 x 10-3 V

The peak value of e.m.f. induced in the coil is 43.99 x 10-3 V.

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APPEARS IN

 2014-2015 (October) (with solutions)
Question 7.6 | 2.00 marks
Solution A Coil of 100 Turns, Each of Area 0.02m^2 is Kept in a Uniform Field of Induction 3.5 X10^-5 T. Concept: Coil Rotating in Uniform Magnetic Induction.
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