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Coefficient of rank correlation between x and y is 0.5 and `sumd_i^2`= 42. Assuming that no ranks are repeated, find the number of pairs of observations.
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Solution
`r=0.5`
`sumd_i^2=42`
`n=?`
`R=1-(6sumd_i^2)/(n(n^2-1))`
`0.5=1-(6(42))/(n(n^2-1))`
`=1-252/(n(n^2-1))`
`252/(n(n^2-1))=1-0.5`
`252/(n(n^2-1))=0.5`
`(n(n^2-1))=252/0.5xx10/10`
`=504`
put n=10
`10(99)=990`
put n=9
`9(80)=720`
put n=8
`8(63)=504`
`therefore n=8`
Concept: Rank Correlation
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