Co-ordinate of point P on a number line is - 7. Find the co-ordinates of points on the number line which are at a distance of 8 units from point P.

#### Solution

The co-ordinates of point P on the number line is −7. Now, there will be two points, one on the left of point P and the other on the right of point P on the number line which are at a distance of 8 units from point P.

Let the point R is on the right of point P and point Q is on the left of point P each at a distance of 8 units from point P.

The co-ordinate of point R will be larger and co-ordinate of point Q will be smaller in comparison to the co-ordinate of point P.

Now, d(P, R) = 8

So, co-ordinate of R − co-ordinate of P = 8

∴ co-ordinate of R = 8 + co-ordinate of P = 8 + (−7) = 8 − 7 = 1

Also, d(Q, P) = 8

So, co-ordinate of P − co-ordinate of Q = 8

∴ co-ordinate of Q = co-ordinate of P − 8 = −7 − 8 = −15

Hence, the co-ordinates of the required points on the number line which are at a distance of 8 units from the point P are 1 and −15.