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# Two Circles Touch Internally. the Sum of Their Areas is 116 π Cm2 And the Distance Between Their Centres is 6 Cm. Find the Radii of the Circles ? - CBSE Class 10 - Mathematics

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ConceptCircles Examples and Solutions

#### Question

Two circles touch internally. The sum of their areas is 116 π cm2 and the distance between their centres is 6 cm. Find the radii of the circles ?

#### Solution

Let r1 be the radius of the bigger circle and r2 be the radius of the smaller circle.
It is given that the two circles touch each other internally.
∴ Difference between their radii = Distance between the centres of the two circles
⇒ r− r2 = 6 cm         .....(1)
Also,

Sum of their areas = 116π cm

$\therefore \pi {r_1}^2 + \pi {r_2}^2 = 116\pi$

$\Rightarrow {r_1}^2 + {r_2}^2 = 116 . . . . . \left( 2 \right)$

From (1) and (2), we have

$\left( r_2 + 6 \right)^2 + {r_2}^2 = 116$

$\Rightarrow {r_2}^2 + 12 r_2 + 36 + {r_2}^2 = 116$

$\Rightarrow 2 {r_2}^2 + 12 r_2 - 80 = 0$

$\Rightarrow {r_2}^2 + 6 r_2 - 40 = 0$

$\Rightarrow {r_2}^2 + 10 r_2 - 4 r_2 - 40 = 0$

$\Rightarrow r_2 \left( r_2 + 10 \right) - 4\left( r_2 + 10 \right) = 0$

$\Rightarrow \left( r_2 + 10 \right)\left( r_2 - 4 \right) = 0$

$\Rightarrow r_2 + 10 = 0 or r_2 - 4 = 0$

$\Rightarrow r_2 = - 10 or r_2 = 4$

Since the radius of a circle cannot be negative, so r2 = 4 cm.
∴ rr2 + 6 = 4 + 6 = 10 cm
Thus, the radii of the circles are 4 cm and 10 cm.

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Solution Two Circles Touch Internally. the Sum of Their Areas is 116 π Cm2 And the Distance Between Their Centres is 6 Cm. Find the Radii of the Circles ? Concept: Circles Examples and Solutions.
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