Question
In fig. XP and XQ are tangents from X to the circle with centre O. R is a point on the circle. Prove that, XA + AR = XB + BR.
Solution
Since lengths of tangents from an exterior point to a circle are equal.
∴ XP = XQ …. (i) [From X]
AP = AR …. (ii) [From A]
BQ = BR …. (iii) [From B]
Now, XP = XQ
⇒ XA + AP = XB + BQ
⇒ XA + AR = XB + BR [Using equations (i) and (ii)]
Is there an error in this question or solution?
Solution for question: In fig. XP and XQ are tangents from X to the circle with centre O. R is a point on the circle. Prove that, XA + AR = XB + BR. concept: Circles Examples and Solutions. For the course CBSE
