From a point P, 10 cm away from the centre of a circle, a tangent PT of length 8 cm is drawn. Find the radius of the circle.
Let O be the centre of the given circle and let P be a point such that OP = 10 cm.
Let PT be the tangent such that PT = 8 cm.
Now, PT is a tangent at T and OT is the radius through T.
∴ OT ⊥ PT.
In the right ∆OTP, we have
`OP^2 = OT^2 + PT^2 ` [by Pythagoras’ theorem]
= √36 cm = 6 cm.
Hence, the radius of the circle is 6 cm
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