#### Question

The figure given below, shows a circle with centre O in which diameter AB bisects the chord CD at point E. If CE = ED = 8 cm and EB = 4cm, find the radius of the circle.

#### Solution

Let the radius of the circle be r cm.

∴ OE = OB- EB = r-4

Join OC

In right ΔOEC,

`OC^2= OE^2+ CE^2`

⇒ `r ^2= (r-4)^2+(8)^2`

⇒ ` r ^2 = r ^2-8r +16+64`

⇒ 8r = 80

∴ r =10 cm

Hence, radius of the circle is 10 cm.

Is there an error in this question or solution?

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The figure given below, shows a circle with centre O in which diameter AB bisects the chord CD at point E. If CE = ED = 8 cm and EB = 4cm, find the radius of the circle. Concept: Chord Properties - the Perpendicular to a Chord from the Center Bisects the Chord (Without Proof).

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