A chord of length 6 cm is drawn in a circle of radius 5 cm. Calculate its distance from the centre of the circle.
Let AB be the chord and O be the centre of the circle.
Let OC be the perpendicular drawn from O to AB.
We know, that the perpendicular to a chord, from the centre of a circle, bisects the chord.
∴ AC = CB = 3 cm
OA2 = OC2 + AC2 (By Pythagoras theorem)
⟹ OC2 = (5)2 – (3)2 = 16
⟹ OC = 4 cm
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