#### Question

In the following figure, O is centre of the circle and ΔABC is equilateral.

Find: (i) ∠ADB, (ii) ∠AEB.

#### Solution

Since ∠ACBand ∠ADBare in the same segment,

∠ADB = ∠ACB = 60°

Join OA and OB

Here, ∠AOB =2 ∠ACB = 2×60° = 120°

`∠AEB=1/2` Reflex ( ∠AOB) = `1/2 (360°- 120°)` 120°

(Angle at the centre is double the angle at the circumference subtended by the same chord)

Is there an error in this question or solution?

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In the Following Figure, O is Centre of the Circle and δAbc is Equilateral. Find: (I) ∠Adb, (Ii) ∠Aeb. Concept: Chord Properties - Chords Equidistant from the Center Are Equal (Without Proof).

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