In the following figure, O is centre of the circle and ΔABC is equilateral.
Find: (i) ∠ADB, (ii) ∠AEB.
Since ∠ACBand ∠ADBare in the same segment,
∠ADB = ∠ACB = 60°
Join OA and OB
Here, ∠AOB =2 ∠ACB = 2×60° = 120°
`∠AEB=1/2` Reflex ( ∠AOB) = `1/2 (360°- 120°)` 120°
(Angle at the centre is double the angle at the circumference subtended by the same chord)
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