Share
Notifications

View all notifications
Advertisement

In the Following Figure, O is Centre of the Circle and δAbc is Equilateral. Find: (I) ∠Adb, (Ii) ∠Aeb. - Mathematics

Login
Create free account


      Forgot password?

Question

In the following figure, O is centre of the circle and ΔABC is equilateral.
Find: (i) ∠ADB, (ii) ∠AEB.

Solution

Since ∠ACBand ∠ADBare in the same segment,
 ∠ADB = ∠ACB = 60°
Join OA and OB
Here, ∠AOB =2 ∠ACB = 2×60° = 120°
 `∠AEB=1/2` Reflex ( ∠AOB) = `1/2 (360°- 120°)` 120°
(Angle at the centre is double the angle at the circumference subtended by the same chord)

  Is there an error in this question or solution?
Advertisement

APPEARS IN

 Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 17: Circles
Exercise 17(A) | Q: 11 | Page no. 258
Advertisement
In the Following Figure, O is Centre of the Circle and δAbc is Equilateral. Find: (I) ∠Adb, (Ii) ∠Aeb. Concept: Chord Properties - Chords Equidistant from the Center Are Equal (Without Proof).
Advertisement
View in app×