Given O is the centre of the circle and ∠AOB = 70°. Calculate the value of:
(i) ∠OCA .
(ii) ∠OCA .
Here, ∠AOB= 2∠ACB
(Angle at the center is double the angle at the circumference by the same chord)
⇒ ∠ACB =`70/2` =35°
Now, OC = OA (radii of same circle)
⇒ ∠OCA = ∠OAC =35°
Video Tutorials For All Subjects
- Chord Properties - Chords Equidistant from the Center Are Equal (Without Proof)