#### Question

Given: ∠CAB = 75° and ∠CBA = 50°. Find the value of ∠DAB + ∠ABD.

#### Solution

In ΔABC, ∠CBA = 50° ,∠CAB = 75°

∠ACB =180° - (∠CBA+CAB)

= 180° - (50° + 75° )

= 180° -125°

= 55°

But ∠ADB = ∠ACB = 55°

(Angle subtended by the same chord on the circle are equal)

Now consider ΔABD,

∠DAB + ∠ABD + ∠ADB =180°

⇒ ∠DAB +∠ABD+ 55° = 180°

⇒ ∠DAB +∠ABD =180° - 55°

⇒ ∠DAB + ∠ABD + 125°

Is there an error in this question or solution?

Solution Given: ∠Cab = 75° and ∠Cba = 50°. Find the Value of ∠Dab + ∠Abd. Concept: Chord Properties - Chords Equidistant from the Center Are Equal (Without Proof).