Advertisement Remove all ads

Choose the correct answer from given options A charge particle after being accelerated through a potential difference 'V' enters in a uniform magnetic field and moves in a circle of radius r. - Physics

MCQ

Choose the correct answer from given options
A charge particle after being accelerated through a potential difference 'V' enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become

Options

  • 2r

  • `sqrt(2r)`

  • 4r

  • `r/sqrt(2)`

Advertisement Remove all ads

Solution

The relation between the accelerating potential and the accelerating voltage is given as: `r = sqrt(2mqV)/(qB)`

As the potential is doubled the radius of curvature becomes `sqrt(2)` times.

Hence, the correct answer is option `sqrt(2r)`.

  Is there an error in this question or solution?
Advertisement Remove all ads
Advertisement Remove all ads

Video TutorialsVIEW ALL [2]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×