# Choose the correct answer from given options A charge particle after being accelerated through a potential difference 'V' enters in a uniform magnetic field and moves in a circle of radius r. - Physics

MCQ

Choose the correct answer from given options
A charge particle after being accelerated through a potential difference 'V' enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become

#### Options

• 2r

• sqrt(2r)

• 4r

• r/sqrt(2)

#### Solution

The relation between the accelerating potential and the accelerating voltage is given as: r = sqrt(2mqV)/(qB)

As the potential is doubled the radius of curvature becomes sqrt(2) times.

Hence, the correct answer is option sqrt(2r).

Is there an error in this question or solution?