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MCQ
Choose the correct alternative:
If y = `1/sqrt(3x^2 - 2x - 1)`, then `("d"y)/("d"x)` = ?
Options
`(-2)/3 (3x - 2) (3x^2 - 2x - 1)^((-3)/2)`
`(-3)/2 (3x - 2) (3x^2 - 2x - 1)^((-3)/2)`
`(3x - 1) (3x^2 - 2x - 1)^((-3)/2)`
`-(3x - 1) (3x^2 - 2x - 1)^((-3)/2)`
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Solution
`-(3x - 1) (3x^2 - 2x - 1)^((-3)/2)`
Concept: Derivatives of Composite Functions - Chain Rule
Is there an error in this question or solution?
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