Answer 1

The solution of `x dy/dx = y` log y is y = e^ax

`x dy/dx = y` log y

∴ `dy/(ylogy) = dx/x`

Integrating on both sides, we get

`int dy/(y logy) = int 1/x dx`

∴ log log(y)= log x + log a

∴ log log(y)= log xa

∴ log(y)= ax

∴ y = e^ax