# Choose the correct alternative : The corner points of the feasible region are (0, 0), (2, 0), (127,37) and (0,1) then the point of maximum z = 7x + y - Mathematics and Statistics

MCQ

Choose the correct alternative :

The corner points of the feasible region are (0, 0), (2, 0), (12/7, 3/7) and (0,1) then the point of maximum z = 7x + y

#### Options

• (0, 0)

• (2, 0)

• (12/7, 3/7)

• (0, 1)

#### Solution

Z = 7x + y
At (0, 0), Z = 0 + 0 = 0
At (2, 0), Z = 7 (2) + 0 = 14

At (12/7, 3/7), "Z" = 7(12/7) + (3)/(7) = (87)/(7) = 12.428

At (0, 1), Z = 0 + 1 = 1.
The maximum value of Z is 14 and it occurs at (2, 0).

Concept: Linear Programming Problem (L.P.P.)
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#### APPEARS IN

Balbharati Mathematics and Statistics 2 (Commerce) 12th Standard HSC Maharashtra State Board
Chapter 6 Linear Programming
Miscellaneous Exercise 6 | Q 1.11 | Page 103