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Solution - Calculate C-Cl bond enthalpy from following reaction: CH3Cl(g) + Cl2(g) → Ch2Cl2(g) + HCl(g) ΔH° = -104KJ - Chemical Thermodynamics and Energetic - Enthalpy of Bond Dissociation

Question

Calculate C-Cl bond enthalpy from following reaction:

CH3Cl(g) + Cl2(g) → Ch2Cl2(g) + HCl(g) ΔH° = -104KJ

If C-H, Cl-Cl and H-Cl bond enthalpies are 414, 243 and 431 KJ-Mol-1 respectively.

Solution

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APPEARS IN

2015-2016 (March)
Question 2.3 | 3 marks
Solution for question: Calculate C-Cl bond enthalpy from following reaction: CH3Cl(g) + Cl2(g) → Ch2Cl2(g) + HCl(g) ΔH° = -104KJ concept: Chemical Thermodynamics and Energetic - Enthalpy of Bond Dissociation. For the courses HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General)
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