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# A Battery of Emf 10 V and Internal Resistance 3 Ω is Connected to a Resistor. If the Current in the Circuit is 0.5 A, What is the Resistance of the Resistor? What is the Terminal Voltage of the Battery When the Circuit is Closed? - CBSE (Science) Class 12 - Physics

#### Question

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?

#### Solution

Emf of the battery, E = 10 V

Internal resistance of the battery, r = 3 Ω

Current in the circuit, I = 0.5 A

Resistance of the resistor = R

The relation for current using Ohm’s law is,

I=E/(R+r)

(R+r)=E/I

=10/0.5=20Omega

therefore R=20-3=17Omega

Terminal voltage of the resistor = V

According to Ohm’s law,

V = IR

= 0.5 × 17

= 8.5 V

Therefore, the resistance of the resistor is 17 Ω and the terminal voltage is

8.5 V.

Is there an error in this question or solution?

#### APPEARS IN

NCERT Solution for Physics Textbook for Class 12 (2018 to Current)
Chapter 3: Current Electricity
Q: 2 | Page no. 127

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Solution A Battery of Emf 10 V and Internal Resistance 3 Ω is Connected to a Resistor. If the Current in the Circuit is 0.5 A, What is the Resistance of the Resistor? What is the Terminal Voltage of the Battery When the Circuit is Closed? Concept: Cells, Emf, Internal Resistance.
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