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A Battery of Emf 10 V and Internal Resistance 3 Ω is Connected to a Resistor. If the Current in the Circuit is 0.5 A, What is the Resistance of the Resistor? What is the Terminal Voltage of the Battery When the Circuit is Closed? - CBSE (Science) Class 12 - Physics

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Question

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?

Solution

Emf of the battery, E = 10 V

Internal resistance of the battery, r = 3 Ω

Current in the circuit, I = 0.5 A

Resistance of the resistor = R

The relation for current using Ohm’s law is,

`I=E/(R+r)`

`(R+r)=E/I`

`=10/0.5=20Omega`

`therefore R=20-3=17Omega`

Terminal voltage of the resistor = V

According to Ohm’s law,

V = IR

= 0.5 × 17

= 8.5 V

Therefore, the resistance of the resistor is 17 Ω and the terminal voltage is

8.5 V.

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Physics Textbook for Class 12 (2018 to Current)
Chapter 3: Current Electricity
Q: 2 | Page no. 127

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Solution A Battery of Emf 10 V and Internal Resistance 3 Ω is Connected to a Resistor. If the Current in the Circuit is 0.5 A, What is the Resistance of the Resistor? What is the Terminal Voltage of the Battery When the Circuit is Closed? Concept: Cells, Emf, Internal Resistance.
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