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# The Equation 4nh3 + 5o2 → 4no + 6 H2o, Represents the Catalytic Oxidation of Ammonia. If 100 Cm3 of Ammonia is Used Calculate the Volume of Oxygen Required to Oxidise the Ammonia Completely - ICSE Class 10 - Chemistry

ConceptCatalytic Oxidation of Ammonia as the Source of Nitric Acid

#### Question

The equation 4NH3 + 5O2 → 4NO + 6 H2O, represents the catalytic oxidation of ammonia. If 100 cm3 of ammonia is used calculate the volume of oxygen required to oxidize the ammonia completely

#### Solution

4NH3 + 5O2 -> 4NO + 6H2O

4 moles of ammonia = 100 cm3

1 mole of ammonia = 25 cm3

4 moles of ammonia requires 5 moles of O2

So, volume of oxygen required = 5 x 25 = 125cm3

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Solution The Equation 4nh3 + 5o2 → 4no + 6 H2o, Represents the Catalytic Oxidation of Ammonia. If 100 Cm3 of Ammonia is Used Calculate the Volume of Oxygen Required to Oxidise the Ammonia Completely Concept: Catalytic Oxidation of Ammonia as the Source of Nitric Acid.
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