#### Question

Three capacitors of capacitances 6 µF each are available. The minimum and maximum capacitances, which may be obtained are

6 µF, 18 µF

3 µF, 12 µF

2 µF, 12 µF

2 µF, 18 µF

#### Solution

2 µF, 18 µF

The minimum capacitance can be obtained by connecting all capacitors in series. It can be calculated as follows :

`1/C = 1/6+1/6+1/6 = 1/2`

⇒ C =2 µF

The maximum capacitance can be obtained by connecting all capacitors in parallel. It can be calculated as follows :

C = 6+6+6 = 18 µF

Is there an error in this question or solution?

Solution Three Capacitors of Capacitances 6 µF Each Are Available. the Minimum and Maximum Capacitances, Which May Be Obtained Are Concept: Capacitors and Capacitance.