Department of Pre-University Education, Karnataka course PUC Karnataka Science Class 12
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Each of the Plates Shown in Figure Has Surface Area ( 96 ∈ 0 ) × 10 − 12 Fm on One Side and the Separation Between the Consecutive Plates is 4⋅0 Mm. the Emf of the Battery Connected is 10 Volts. - Physics

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Question

Each of the plates shown in figure has surface area `(96/∈_0) xx 10^-12` Fm on one side and the separation between the consecutive plates is 4⋅0 mm. The emf of the battery connected is 10 volts. Find the magnitude of the charge supplied by the battery to each of the plates connected to it.

Solution

Here, three capacitors are formed and each of them has area A.

Now ,

`A = 96/∈_0 xx 10^-12  "F" - "m"`

d = 4 mm

`= 3 xx 10^-3  "m"`

The capacitance of the capacitors is given by

`C = (∈_0A)/d = (∈_0(96/∈_0) xx 10^-12)/(4 xx 10^-3)` = `24 xx 10^-9  "F"`

Because the three capacitors are arranged in series, the equivalent capacitance is given by

`C_(eq) = (24 xx 10^-9)/3 = 8 xx 10^-9 F`

The total charge on the capacitor is given by

Q = CeqV

`⇒ Q = 8 xx 10^-9 xx 10`

`⇒ Q = 8 xx 10^-8  "C"`

The charge on a single plate is given by

`Q_p = 2 xx 8 xx 10^-8`

`⇒ Q_p = 16 xx 10^-8 = 0.16  "uC"`

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Solution Each of the Plates Shown in Figure Has Surface Area ( 96 ∈ 0 ) × 10 − 12 Fm on One Side and the Separation Between the Consecutive Plates is 4⋅0 Mm. the Emf of the Battery Connected is 10 Volts. Concept: Capacitors and Capacitance.
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