The Temperature of 170g of Water at 50°C is Lowered to 5°C by Adding a Certain Amount of Ice to It. Find the Mass of Ice Added. - ICSE Class 10 - Physics
why create a profile on Shaalaa.com?
1. Inform you about time table of exam.
2. Inform you about new question papers.
3. New video tutorials information.
The temperature of 170g of water at 50°C is lowered to 5°C by adding a certain amount of ice to it. Find the mass of ice added.
M_w = 170 gm,S_w = 1 `"cal/gm"^@C` = 4200 J / `kg^@C`
`triangle T = 5^@C, L_f = 80 cal/gm` = 336000 J/kg
Amount of heat given by water = Amount of heat absorb by ice .....[Principle of calorimetry]
`M_wS_wtriangleT = M_"ice" xx L_f`
`(170)(1)(5) = M_"ice" xx (80)`
:. `M_"ice" = (170xx1xx5)/(80)` = 10.625 gm
Is there an error in this question or solution?
Solution The Temperature of 170g of Water at 50°C is Lowered to 5°C by Adding a Certain Amount of Ice to It. Find the Mass of Ice Added. Concept: Calorimetry - Specific Heat Capacity.