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Silver crystallises in FCC structure. If density of silver is 10.51 gcm-3, calculate the volume of unit cell. - CBSE (Science) Class 12 - Chemistry

ConceptCalculations Involving Unit Cell Dimensions

Question

Silver crystallises in FCC structure. If density of silver is 10.51 gcm-3, calculate the volume of unit cell.

[Atomic mass of slive (Ag) = 108 gm-1]

Solution

Density of silver is 10.51 g cm−3. Unit cell of FCC has 4 atoms

Mass of unit cell = (4*108)/(6.022*10^23) =71.74*10-23

"Density of silver" = "Mass of unit cell" / "Volume of unit Cell"

"Volume of unit cell" = "Mass of unit cell"/"Density of silver" = (71.74*10^-23)/10.51

Volume of unit cell = 68.27*10-24cm3

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2015-2016 (March) (with solutions)
Question 2.1 | 3.00 marks

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Solution Silver crystallises in FCC structure. If density of silver is 10.51 gcm-3, calculate the volume of unit cell. Concept: Calculations Involving Unit Cell Dimensions.
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