#### Question

Silver crystallises in FCC structure. If density of silver is 10.51 gcm^{-3}, calculate the volume of unit cell.

[Atomic mass of slive (Ag) = 108 gm^{-1}]

#### Solution

Density of silver is 10.51 g cm−3. Unit cell of FCC has 4 atoms

Mass of unit cell = `(4*108)/(6.022*10^23)` =71.74*10^{-23}

`"Density of silver" = "Mass of unit cell" / "Volume of unit Cell"`

`"Volume of unit cell" = "Mass of unit cell"/"Density of silver" = (71.74*10^-23)/10.51`

Volume of unit cell = 68.27*10^{-24}cm^{3}

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#### APPEARS IN

Solution Silver crystallises in FCC structure. If density of silver is 10.51 gcm-3, calculate the volume of unit cell. Concept: Calculations Involving Unit Cell Dimensions.