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# Solution for Niobium Crystallises as Body Centred Cube (Bcc) and Has Density of 8.55 Kg / Dm-3 . Calculate the Attomic Radius of Niobium. - HSC Science (Electronics) 12th Board Exam - Chemistry

ConceptCalculations Involving Unit Cell Dimensions

#### Question

Niobium crystallises as body centred cube (BCC) and has density of 8.55 Kg / dm-3 . Calculate the attomic radius of niobium.

(Given : Atomic mass of niobium = 93).

#### Solution

Crystal structure of Niobium = bcc

Density (d) = 8.55 kg dm-3

Atomic mass of Niobium = 93

d=(nxxM)/(VxxN_A)

No. of atoms per unit cell (n) in bcc = 2

Total volume of unit cell = a3

d=(2xx93)/(a^3xx6.023xx10^23

a^3=(2xx93)/(8.55xx6.023xx10^23)=36.12xx10^-24

a=root(3)(36.12xx10^-24)

a= 3.305 x 10-8

In BCC unit cell,

r=(sqrt3xxa)/4=(sqrt3xx3.305xx10^-8)/4=1.431xx10^-8

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Solution for question: Niobium Crystallises as Body Centred Cube (Bcc) and Has Density of 8.55 Kg / Dm-3 . Calculate the Attomic Radius of Niobium. concept: Calculations Involving Unit Cell Dimensions. For the courses HSC Science (Electronics), HSC Science (Computer Science), HSC Science (General)
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