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Calculate the Wavelength of Radiation Emitted When Electron in a Hydrogen Atom Jumps from N=Infinity to N=1 - Physics

Calculate the wavelength of radiation emitted when electron in a hydrogen atom jumps from n = `oo` to n = 1.

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Solution

The electron in the hydrogen atom jumps from n2 = `oo`to n1 = 1. Now, we know that

`:.1/lambda= R(1/(n_1^2)-1/(n_2^2))`

`:.1/lambda=1.097xx10^7(1/1-1/oo)=1.097xx10^7`

`:.1/(1.097xx10^7)=9.116xx10^-8" " m= 911.6xx10^(-10)m`

 ∴ λ = 911.6 Å

Concept: Dual Nature of Radiation
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