Advertisement Remove all ads

# Calculate the Wavelength of Radiation Emitted When Electron in a Hydrogen Atom Jumps from N=Infinity to N=1 - Physics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

Calculate the wavelength of radiation emitted when electron in a hydrogen atom jumps from n = oo to n = 1.

Advertisement Remove all ads

#### Solution

The electron in the hydrogen atom jumps from n2 = ooto n1 = 1. Now, we know that

:.1/lambda= R(1/(n_1^2)-1/(n_2^2))

:.1/lambda=1.097xx10^7(1/1-1/oo)=1.097xx10^7

:.1/(1.097xx10^7)=9.116xx10^-8" " m= 911.6xx10^(-10)m

∴ λ = 911.6 Å

Concept: Dual Nature of Radiation
Is there an error in this question or solution?

#### Video TutorialsVIEW ALL [2]

Advertisement Remove all ads
Share
Notifications

View all notifications

Forgot password?