Calculate the wavelength of an electron moving with a velocity of 2.05 × 10^{7} ms^{–1}.

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#### Solution

According to de Broglie’s equation,

`lambda = h/(mv)`

λ = wavelength of moving particle

*m *= mass of particle

*v* = velocity of particle

h = Planck’s constant

Substituting the values in the expression of *λ**:*

`lambda = (6.626 xx 10^(-34) Js)/((9.10939xx10^(-31)kg)(2.05xx10^7 ms^(-1)))

`lambda = 3.548 xx 10^(-11)m`

Hence, the wavelength of the electron moving with a velocity of 2.05 × 10^{7} ms^{–1} is 3.548 × 10^{–11} m.

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