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Calculate the Wavelength of an Electron Moving with a Velocity of 2.05 × 107 Ms–1. - Chemistry

Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms–1.

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Solution

According to de Broglie’s equation,

`lambda = h/(mv)`

λ = wavelength of moving particle

= mass of particle

v = velocity of particle

h = Planck’s constant

Substituting the values in the expression of λ:

`lambda = (6.626 xx 10^(-34) Js)/((9.10939xx10^(-31)kg)(2.05xx10^7 ms^(-1)))

`lambda = 3.548 xx 10^(-11)m`

Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.

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APPEARS IN

NCERT Class 11 Chemistry Textbook
Chapter 2 Structure of Atom
Q 20 | Page 66
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