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# Calculate the Wavelength of an Electron Moving with a Velocity of 2.05 × 107 Ms–1. - CBSE (Science) Class 11 - Chemistry

ConceptTowards Quantum Mechanical Model of the Atom Dual Behaviour of Matter

#### Question

Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms–1.

#### Solution

According to de Broglie’s equation,

lambda = h/(mv)

λ = wavelength of moving particle

= mass of particle

v = velocity of particle

h = Planck’s constant

Substituting the values in the expression of λ:

lambda = (6.626 xx 10^(-34) Js)/((9.10939xx10^(-31)kg)(2.05xx10^7 ms^(-1)))

lambda = 3.548 xx 10^(-11)m`

Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.

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Solution Calculate the Wavelength of an Electron Moving with a Velocity of 2.05 × 107 Ms–1. Concept: Towards Quantum Mechanical Model of the Atom - Dual Behaviour of Matter.
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