Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms–1.
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Solution
According to de Broglie’s equation,
`lambda = h/(mv)`
λ = wavelength of moving particle
m = mass of particle
v = velocity of particle
h = Planck’s constant
Substituting the values in the expression of λ:
`lambda = (6.626 xx 10^(-34) Js)/((9.10939xx10^(-31)kg)(2.05xx10^7 ms^(-1)))
`lambda = 3.548 xx 10^(-11)m`
Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.
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