# Calculate the Wavelength of an Electron Moving with a Velocity of 2.05 × 107 Ms–1. - Chemistry

Numerical

Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms-1.

#### Solution

According to de Broglie’s equation,

lambda = "h"/("mv")

λ = wavelength of moving particle

m = mass of particle

v = velocity of particle

h = Planck’s constant

Substituting the values in the expression of λ:

lambda = (6.626 xx 10^(-34)  "Js")/((9.10939xx10^(-31) "kg")(2.05xx10^7 "ms"^(-1)))

lambda = 3.548 xx 10^(-11) " m"

Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.

Concept: Towards Quantum Mechanical Model of the Atom - Dual Behaviour of Matter
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#### APPEARS IN

NCERT Chemistry Part 1 and 2 Class 11
Chapter 2 Structure of Atom
EXERCISES | Q 2.20 | Page 70

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