Question

Calculate the number of unpaired electrons in Ti³⁺, Mn²⁺ and calculate the spin only magnetic moment.

Answer 1

Ti³⁺:

Ti (Z = 22)

Electronic configuration [Ar] 3d² 4s²

Ti³⁺ – Electronic configuration [Ar] 3d¹

So, the number of unpaired electrons in Ti³⁺ is equal to 1.

Spin only magnetic moment of Ti³⁺ = `sqrt(1 (1 + 2)) = sqrt3` = 1.73 µ_B

Mn²⁺:

Mn (Z = 25)

Electronic configuration [Ar] 3d⁵ 4s²

Mn²⁺ – Electronic configuration [Ar] 3d⁵

Mn²⁺ has 5 unpaired electrons.

Spin only magnetic moment of Mn²⁺ = `sqrt(5 (5 + 2)) = sqrt35` = 5.91 µ_B