Tamil Nadu Board of Secondary EducationHSC Science Class 12th

# Calculate the number of unpaired electrons in Ti3+, Mn2+ and calculate the spin only magnetic moment. - Chemistry

Numerical

Calculate the number of unpaired electrons in Ti3+, Mn2+ and calculate the spin only magnetic moment.

#### Solution

Ti3+:

Ti (Z = 22)

Electronic configuration [Ar] 3d4s2

Ti3+ – Electronic configuration [Ar] 3d1

So, the number of unpaired electrons in Ti3+ is equal to 1.

Spin only magnetic moment of Ti3+ = sqrt(1 (1 + 2)) = sqrt3 = 1.73 µB

Mn2+:

Mn (Z = 25)

Electronic configuration [Ar] 3d4s2

Mn2+ – Electronic configuration [Ar] 3d5

Mn2+ has 5 unpaired electrons.

Spin only magnetic moment of Mn2+ = sqrt(5 (5 + 2)) = sqrt35 = 5.91 µB

Concept: General Trend in Properties
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#### APPEARS IN

Tamil Nadu Board Samacheer Kalvi Class 12th Chemistry Volume 1 and 2 Answers Guide
Chapter 4 Transition and Inner Transition Elements
Evaluation | Q 10. | Page 128
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