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Calculate the correlation coefficient from the following data, and interpret it. X 1 3 5 7 9 11 13 Y 12 10 8 6 4 2 0 - Mathematics and Statistics

Sum

Calculate the correlation coefficient from the following data, and interpret it.

X 1 3 5 7 9 11 13
Y 12 10 8 6 4 2 0
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Solution

  xi yi xi2 yi2 xiyi
  1 12 1 144 12
  3 10 9 100 30
  5 8 25 64 40
  7 6 49 36 42
  9 4 81 16 36
  11 2 121 4 22
  13 0 169 0 0
Total 49 42 455 364 182

From the table, we have
n = 7, `sum"x"_"i"` = 49, `sum"y"_"i"` = 42, `sum"x"_"i"^2` = 455, `sum"y"_"i"^2` = 364, `sum"x"_"i""y"_"i"^2` = 182

∴ `bar"x" = (sum"x"_"i")/"n" = 49/7` = 7,

`bar"y" = (sum"y"_"i")/"n" = 42/7` = 6

Cov (X, Y) = `1/"n" sum"x"_"i""y"_"i" - bar"x" bar"y"`

= `1/7 xx 182 - (7 xx 6)`

= 26 − 42

∴ Cov (X, Y) = – 16

`sigma_"x"^2 = (sum"x"_"i"^2)/"n" - (bar"x")^2`

= `455/7 - (7)^2`
= 65 – 49
∴ `sigma_"x"^2` = 16

∴ `sigma_"x"` = 4

`sigma_"y"^2 = (sum"y"_"i"^2)/"n" - (bar"y")^2`

= `364/7 - (6)^2`

= 52 – 36
`sigma_"y"^2` = 16
∴ `sigma_"y"` = 4
Thus, the coefficient of correlation between X and Y is

r = `("Cov (X, Y)")/(sigma_"x" sigma_"y")`

= `(-16)/(4 xx 4)`

= – 1
∴ The value of r indicates perfect negative correlation between x and y.

Concept: Interpretation of Value of Correlation Coefficient
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APPEARS IN

Balbharati Mathematics and Statistics 2 (Commerce) 11th Standard HSC Maharashtra State Board
Chapter 5 Correlation
Miscellaneous Exercise 5 | Q 6 | Page 64
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