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Calculate the binding energy of an alpha particle given its mass to be 4.00151 u. - Physics

Numerical

Calculate the binding energy of an alpha particle given its mass to be 4.00151 u.

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Solution

Data: M = 4.00151 u, mp = 1.00728 u, mn = 1.00866 u, 1 u = 931.5 MeV/c2

The binding energy of an alpha particle =

(Zmp + Nmn - M)c2

= (2mp + 2mn - M)c2

= [(2)(1.00728 u) + 2(1.00866 u) - 4.00151 u]c2

= (2.01456 + 2.01732 - 4.00151)(931.5) MeV

= 28.289655 MeV

= 28.289655 × 106 eV × 1.602 × 10-10 J

= 4.532002731 × 10-12 J

Concept: Mass-energy and Nuclear Binding Energy - Nuclear Binding Energy
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APPEARS IN

Balbharati Physics 12th Standard HSC Maharashtra State Board
Chapter 15 Structure of Atoms and Nuclei
Exercises | Q 10 | Page 342
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