Sum

Calculate the tension in the string shown in the following figure. The pulley and the string are light and all the surfaces are frictionless. Take g = 10 m/s^{2}.

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#### Solution

The free-body diagrams for both the bodies are shown below:

T + ma =mg ...(i)

and T = ma ...(ii)

From equations (i) and (ii), we get:

ma + ma = mg

⇒ 2ma = g

\[\Rightarrow a = \frac{g}{2} = \frac{10}{5} = 5 m/ s^2\]

From equation (ii),

T = ma = 5 N

Concept: Newton’s Second Law of Motion

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