Question

The surface tension of water at 0°C is 75.5 dyne/cm. Calculate surface tension of water at 25°C.

(α for water = 2.7×10^-3/°C)

Answer 1

Given:

T₀ = 75.5 dyne/cm

α_water = 2.7 × 10^-3/°C

To find:

Surface tension of water at 25°C

Formula:

T₁ = T₀(1 - αΔt)

Solution:

T₂₅ = T₀(1 - αΔt)

T₂₅ = T₀(1 - α(25 - 0))

T₂₅ = 75.5(1 - 2.7 × 10^-3 × 25)

T₂₅ = 75.5(1 - 0.0675)

T₂₅ = 70.4 dyne/cm

The surface tension of water at 25°C is 70.4 dyne/cm.