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Calculate the standard enthalpy of combustion of CH3COOH(l) from the following data: - Chemistry

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Question

Calculate the standard enthalpy of combustion of CH3COOH(l) from the following data:

`Delta_fH^@(CO_2)=-393.3 kJ mol^-1`

`Delta_fH^@(H_2O)=-285.8 kJ mol^-1`

`Delta_fH^@(CH_3COOH)=-483.2 kJ mol^-1`

Solution

`C_((s))+O_(2(g))->CO_(2(g))`                                     `Delta_fH^@=-393.3 kJ mol^-1`...(1)

`H_(2(g))+1/2O_(2(g))->H_2O_((l))`                               `Delta_fH^@=-285.8 kJ mol^-1`...(2)

`2C_((s))+2H_(2(g))+O_(2(g))->CH_3COOH`        `Delta_fH^@=-483.2 kJ mol^-1` ...(3)

The required equation is,
CH3COOH(l) + 2O2(g) →2CO2(g) + 2H2O(l)

Multiplying equation (1) and equation (2) by 2, then adding to reverse of equation (3).

`2C_((s))+2O_(2(g))->2CO_(2(g))`                                  `Delta_fH^@=-786.6 kJ mol^-1`

`2H_(2(g))+1O_(2(g))->2H_2O_((l))`                               `Delta_fH^@=-571.6 kJ mol^-1`

`CH_3COOH_(l)->2C_((s))+2H_(2(g))+O_(2(g))`          `Delta_fH^@= 483.2 kJ mol^-1`

--------------------------------------------------------------------------------------------

`CH_3COOH_(l)+2O_(2(g))->2CO_(2(g))+2H_2O_((l))`          `Delta_fH^@=-875 kJ mol^-1`

 

 

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APPEARS IN

 2016-2017 (July) (with solutions)
Question 3.2 | 3.00 marks

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Solution Calculate the standard enthalpy of combustion of CH3COOH(l) from the following data: Concept: Chemical Thermodynamics and Energetic - Enthalpy of Bond Dissociation.
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