Advertisement Remove all ads

Calculate the Released Energy. - Physics

A nucleus with mass number A = 240 and BE/A = 7.6 MeV breaks into two fragments, each of A = 120 with BE/A = 8.5 MeV. Calculate the released energy.

Advertisement Remove all ads

Solution

The binding energy of the nucleus of mass number 240, B1=7.6×240=1824 MeV

The binding energy of each product nucleus, B2=8.5×120=1020 MeV

Then, the energy released as the nuclues breaks is given by 

E=2B2B1=2×10201824=216 MeV

  Is there an error in this question or solution?
Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×