Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Numerical
Calculate the period of revolution of Jupiter around the Sun. The ratio of the radius of Jupiter’s orbit to that of the Earth’s orbit is 5.
(Period of revolution of the Earth is 1 year)
Advertisement Remove all ads
Solution
Given that `"r"_"j"^3/"r"_"E" = 5`
`"T"_"J"^2/"T"_E^2=r_J^3/r_E^3`
Or, `T_J/T_E= (r_J/r_E)^"3/2"`
`T_J/1=(5)^"3/2" = 11.18 "years"`
Thus, the period of revolution of Jupiter is 11.18 years.
Concept: Newton’s Law of Gravitation
Is there an error in this question or solution?