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Calculate the Percentage Composition of Oxygen in Lead Nitrate - Chemistry

Sum

Calculate the percentage composition of oxygen in lead nitrate [Pb(NO3)2]. [Pb = 207, N= 14, O = 16]

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Solution

Pb + (N)2 + (O)6
207 + 2 x 14 + 6 x 16 = 331.
So, the molecular mass of Pb(NO3)2 = 331.
331 by weight of Pb(NO3)2 contain 96 parts by weight of oxygen .
100 parts will contain = 96 x 100 / 331 = 29 ‰
So, the percentage composition of oxygen in lead nitrate is 29‰

Concept: Relationship Between Vapour Density and Relative Molecular Mass
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APPEARS IN

Frank ICSE Class 10 Chemistry Part 2
Chapter 5 Mole Concept And Stoichiometry
Exercise | Q 4 | Page 116
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