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Calculate the Percentage of Boron (B) in Borax (Na2b4o7.10h2o). - Chemistry

Sum

Calculate the percentage of boron (B) in borax (Na2B4O7.10H2O). [H = 1, B = 11, O = 16, Na = 23],
answer correct to 1 decimal place.

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Solution

Molecular mass of borax Na2B4O7.10H2O = 382
382 parts by weight of borax contain 44 parts by weight of boron
So,100 parts will contain = 44 x 100/382 = 11.5‰
Percentage of boron (B) in borax (Na2B4O7.10H2O) = 11.5‰.

Concept: Relationship Between Vapour Density and Relative Molecular Mass
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APPEARS IN

Frank ICSE Class 10 Chemistry Part 2
Chapter 5 Mole Concept And Stoichiometry
Exercise | Q 9.1 | Page 117
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