Numerical
Calculate the percentage atom economy for the following reaction.
CH3NH2+COCL2 →CH3N=C=O+2HCL
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Solution
CH3NH2+COCl2 →CH3N=C=O+2HCl
(41) (99) (57)
% Atom Economy =`"Molecular weight of the product"/"Total molecular weight of reactant"xx100`
`(57xx100)/(41+99)`
= 43.86%
CH3NH2 = 12+13+14+2
= 41
COCl2=12+16+2X35.5
= 99
CH3 = C = O = 12+3+14+16
= 57
Concept: Numerical on Atom Economy
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