Share

# Calculate the number of unpaired electrons in gaseous ions: Mn3+, Cr3+, V3+ and Ti3+. Which one of these is the most stable in aqueous solution? - CBSE (Science) Class 12 - Chemistry

ConceptGeneral Properties of the Transition Elements (D-block)

#### Question

Calculate the number of unpaired electrons in the following gaseous ions: Mn3+, Cr3+, V3+ and Ti3+. Which one of these is the most stable in aqueous solution?

#### Solution

 Gaseous ions Number of unpaired electrons 1 Mn^(3+), [Ar]3d^4 4 2 Cr^(3+), [Ar]3d^3 3 3 V^(3+), [Ar]3d^2 2 4 Ti^(3+), [Ar]3d^1 1

Cr3+ is the most stable in aqueous solutions owing to a t_(2g)^3 configuration.

Is there an error in this question or solution?

#### APPEARS IN

NCERT Solution for Chemistry Textbook for Class 12 (2018 to Current)
Chapter 8: The d-block and f-block Elements
Q: 24 | Page no. 235

#### Video TutorialsVIEW ALL 

Solution Calculate the number of unpaired electrons in gaseous ions: Mn3+, Cr3+, V3+ and Ti3+. Which one of these is the most stable in aqueous solution? Concept: General Properties of the Transition Elements (D-block).
S