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Calculate the Number of Molecules Present in a Drop of Chloroform (Chcl3) Weighing 0.0239 G. - Science

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Short Note

Calculate the number of molecules present in a drop of chloroform (CHCl3) weighing 0.0239 g.

(Atomic masses : C = 12 u ; H = 1 u ; Cl = 35.5 u)

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Solution

Mass of chloroform = 0.0239g

Molar mass of chloroform = (1 × 12) + (1 × 1) + (3 × 35.5) = 119.5g

Number of molecules in 119.5g of chloroform = 6.022 × 1023

Number of molecules in 1g of chloroform = 6.022 × 1023/119.5

Number of molecules in 0.0239g of chloroform = 0.0239 × 6.022 × 1023/119.5

Hence, a drop of chloroform weighing 0.0239g has 1.2 × 1020 molecules.

Concept: Molecules
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APPEARS IN

Lakhmir Singh Class 9 Chemistry - Science Part 2
Chapter 3 Atoms and Molecules
Short Answers | Q 24 | Page 172

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