#### Question

Calculate the kinetic energy of 10 gram of Argon molecules at 127°C.

[Universal gas constant R = 8320 J/k mole K. Atomic weight of Argon = 40]

#### Solution

Given:

R = 8320 J/k mole K

M_{0} = 40

T = 127°C = 127 + 273 = 400K

To find:

K.E for 10g = ?

Formula:

`K.E=(3RT)/(2M_o)xxM`

Solution:

`K.E=(3RT)/(2M_o)xxM`

`K.E=(3xx8320xx400xx0.01)/(2xx40)`

K.E = 1248J

The kinetic energy of 10 grams of Argon molecules at 127°C is 1248J of Argon.

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#### APPEARS IN

Solution Calculate the Kinetic Energy of 10 Gram of Argon Molecules At 127°C. Concept: Phase of K.E (Kinetic Energy).