Advertisement Remove all ads

Calculate the Kinetic Energy of 10 Gram of Argon Molecules At 127°C. - Physics

Calculate the kinetic energy of 10 gram of Argon molecules at 127°C.
[Universal gas constant R = 8320 J/k mole K. Atomic weight of Argon = 40]

Advertisement Remove all ads

Solution

Given:

R = 8320 J/k mole K

M0 = 40

T = 127°C = 127 + 273 = 400K

To find:

K.E for 10g = ?

Formula:

`K.E=(3RT)/(2M_o)xxM`

Solution:

`K.E=(3RT)/(2M_o)xxM`

`K.E=(3xx8320xx400xx0.01)/(2xx40)`

K.E = 1248J

The kinetic energy of 10 grams of Argon molecules at 127°C is 1248J of Argon.

Concept: Phase of K.E (Kinetic Energy)
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×