Maharashtra State Board course HSC Science (Electronics) 12th Board Exam
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Calculate the Internal Energy at 298k for the Formation of One Mole of Ammonia, If the Enthalpy Change at Constant Pressure is – 42.0 Kj Mol-1. - Physics

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Question

Calculate the internal energy at 298K for the formation of one mole of ammonia, if the enthalpy change at constant pressure is – 42.0 kJ mol-1.

(Given: R = 8.314 J K-1 mol-1)

Solution

Formation of 1 mole of ammonia

`1/2 N_(2(g)) + 3/2 H_(2(g)) -> NH_(3(g))`

Δn = (no.of moles of gaseous product) - (no.of moles of gaseous reactant)

`= 1 - (1/2 + 3/2)`

= -1

ΔH = ΔU + PΔV

PΔV = -ΔnRT

`=-(-1)xx8.314xx298`

= 2477 J

= 2.477 KJ

ΔH = -42.0 KJ

∴ -42.0 KJ = ΔU + 2.477

ΔU = -42 - 2.477

= -44.47 KJ

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APPEARS IN

 2017-2018 (March) (with solutions)
Question 3.4 | 3.00 marks
Solution Calculate the Internal Energy at 298k for the Formation of One Mole of Ammonia, If the Enthalpy Change at Constant Pressure is – 42.0 Kj Mol-1. Concept: Chemical Thermodynamics and Energetic - First Law of Thermodynamics.
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