Advertisement Remove all ads

Calculate the Energy Required for the Process The Ionization Energy for the H Atom in the Ground State is 2.18 ×10–18 J Atom–1 - Chemistry

Calculate the energy required for the process 

`He_(" "(g))^+ ->He_(" " (g))^(2+) + e^(-)`

The ionization energy for the H atom in the ground state is 2.18 ×10–18 J atom–1

Advertisement Remove all ads

Solution

Energy associated with hydrogen-like species is given by,

`E_n = -2.18 xx 10^(-18)  (Z^2/n^2)J`

For ground state of hydrogen atom,

`triangleE = E_prop - E_1`

`= 0 - [-2.18 xx 10^(-18)  {(1)^2/(1)^2}]J`

`triangleE =2.18 xx 10^(-18) J`

For the given process,

`He_(" "(g))^+ -> He_(" "(g))^(2+) + e^(-)`

An electron is removed from n = 1 to n = ∞.

`triangleE = E_prop - E_1`

`= 0-[-2.18 xx 10^(-18) {(2)^2/(1)^2}]`

`triangleE = 8.72 xx 10^(-18) J`

∴ The energy required for the process is `8.72 xx 10^(-18)J`

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

NCERT Class 11 Chemistry Textbook
Chapter 2 Structure of Atom
Q 34 | Page 67
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×