# Calculate the Energy Required for the Process The Ionization Energy for the H Atom in the Ground State is 2.18 ×10–18 J Atom–1 - Chemistry

Calculate the energy required for the process

He_(" "(g))^+ ->He_(" " (g))^(2+) + e^(-)

The ionization energy for the H atom in the ground state is 2.18 ×10–18 J atom–1

#### Solution

Energy associated with hydrogen-like species is given by,

E_n = -2.18 xx 10^(-18)  (Z^2/n^2)J

For ground state of hydrogen atom,

triangleE = E_prop - E_1

= 0 - [-2.18 xx 10^(-18)  {(1)^2/(1)^2}]J

triangleE =2.18 xx 10^(-18) J

For the given process,

He_(" "(g))^+ -> He_(" "(g))^(2+) + e^(-)

An electron is removed from n = 1 to n = ∞.

triangleE = E_prop - E_1

= 0-[-2.18 xx 10^(-18) {(2)^2/(1)^2}]

triangleE = 8.72 xx 10^(-18) J

∴ The energy required for the process is 8.72 xx 10^(-18)J

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#### APPEARS IN

NCERT Class 11 Chemistry Textbook
Chapter 2 Structure of Atom
Q 34 | Page 67